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cement volumes for m grade concrete

Hence revised ( Cement ) content = 141/0.36 = 392 kg /cum. Cement quantities per cum. Cement = 392 kg/cum which is less than maximum cement content of 450 kg/cum. Hence OK Volume of cement = ( Mass of cement /( Specific gravity of cement X1000) = 392/(3.15X1000) = 0.124 cum. Water quantities per cum. Water = 141 kg /cum

1m3 ofconcretematerialcementsand aggregate and water

1m3 of concrete material cement sand aggregate and water. Cement quantity for 1m3 of m20 concrete: part of cement= 1/5.5, density of cement =1440kg/m3, dry volume = 1.54m3, weight = volume × density, weight of cement = 1/5.5×1.54m3 ×1440 kg/m3 = 403kg, so 403kg cement is required for 1m3 of M20 grade of concrete

concrete calculator

Total up the step volumes then the total concrete you need is Volume in Cubic Feet = Volume in Cubic Feet Under Platform + Volume in Cubic Feet Under Steps Volume in Cubic Yards (yd 3) = Volume in Cubic Feet (ft 3) / 27 Volume in Cubic Meters (m 3) = Volume in Cubic Feet (ft 3) x 0.0283

concrete mix design for m40 grade- online civil

Dec 16, 2020 · From Table-6.6 for nominal maximum size of aggregate 20 mm. See More Calculate Quantities of Materials for Concrete. = 186 litre. This is for 50 mm slump. Increase 3% water for every 25 mm slump over and above 50 mm slump. We have slump value of …

m30grade of concrete mix design procedure with opc53cement

Volume of 1 cube mould = 0.150 x 0.150 x 0.150 = 0.003375 cum. so concrete quantity for 1 cube = 0.003375 cum. concrete quantity for 12 cubes = 0.003375 x 12 = 0.0405 cum. We should take a little more quantity of concrete because it will stick on a trial mix drum and slump test purposes

different grades ofconcrete, their strength and selection

Grade of concrete is denoted by prefixing M to the desired strength in MPa. For example, for a grade of concrete with 20 MPa strength, it will be denoted by M20, where M stands for Mix. These grade of concrete is converted into various mix proportions. For example, for M20 concrete, mix proportion will be 1:1.5:3 for cement:sand:coarse aggregates

concretecalculator - how muchconcretedo i need? - the

Apr 23, 2018 · Essentially you are solving for volume and then converting to cubic yards. For concrete, the formula for volume is as follows: length x width x thickness. To determine how many bags of concrete you will need, divide the total cubic yards needed by the yield. Use the following yields per each bag size: 40 pound bag yields .011 cubic yards

Dec 16, 2019 · For one cu m, calculate the cement, sand, and aggregate with 0.5 ratios of water for the following grades of concrete M10, M15, M20, M25, and M30. DRY VOLUME 1.54: GRADE OF CONCRETE: PROPORTION: CEMENT: SAND: DENSITY 1440: DENSITY 1500: M10: 1:03:06: 0.154 m 3: 0.462 m 3 (C:S:A) 221.76 kg: 693 kg: 5.43 C.FT: 16.31: M15: 1:02:04: 0.22 m 3: 0.44 m 3 (C:S:A) 316.8 kg: 660 kg: …

how to calculate ofcement, sand and aggregate for m10

Wet volume of concrete = 1 m³ Dry volume = Wet volume x 1.54 (You can also take it as 1.50 to 1.55, But it became standard practice to considering 1.54 as multiplication factor). Dry volume of concrete = 1 x 1.54 =1.54 m³ 1- Find-out quantity of Cement

concrete mix design calculation for m15 gradeas per is

Finally, C = 336.14 Kg / m 3 of concrete But from table 5 of IS456-2000, Minimum cement content required for moderate exposure condition for M15 grade concrete is = 240 Kg/m 3 of concrete. Greater of above two values will be the cement content. Hence, C = 336.14Kg

quantity analysis for materials in1 cu.m cement concrete

The volume of cement = (ratio of cement/sum of the ratio) x total volume = (1/5.5) x 1.54 = 0.28 m 3 Weight of 1 m 3 Cement is 1440 KG. So, weight of 0.28 m 3 cement = 0.28 x 1440 = 403.2 KG. Now, the cement is specified in bags, not in Kg

what is thevolumeof a 20kg bag ofconcrete?

45 cubic feet and an 80-pound bag yields. 60 cubic feet. One 50-pound bag of Quikrete Fast Setting Concrete Mix yields about. 375 cubic feet. How much concrete does a 40kg bag make? MIXING RATIO We generally recommend a 5 to 1 ratio with cement to produce good strong concrete

differentgrades of concrete| based on is, american

c. M35 Grade. M-35 Mix Designs as per IS-10262-2009; Used as Reinforced Cement Concrete(RCC). Used for construction of slabs,beams,columns,etc. d. M40 Grade. M-40 Mix Designs as per IS-10262-2009; Used as Prestressed Concrete. Used for construction of slabs,beams,columns,etc. e. M45 Grade. M-45 Mix Designs as per IS-10262-2009

Question: Design M45 Grade Concrete: Refer IS 10602 Grade Designation: M 45 Type Of Cement: OPC 53 Grade Confirming To IS 8112 Maximum Nominal Size Of Aggregate: 20 Mm Minimum Cement Content: 360 Kg/m3 Maximum Water-cement Ratio: 0.40 Workability: 50-100 Mm (slump) Exposure Condition: Extreme (for Reinforced Concrete) Method Of Concrete Placing: Pumping Degree

how to calculate quantities ofcement, sand and aggregate

The ratio of dry volume to the wet volume of concrete is 1.54. So 1.54 Cum of dry materials (cement, sand and aggregate) is required to produce 1 Cum of concrete Volume of Cement required = 1/ (1+2+4) X 1.54 = 1/7 X 1.54 = 0.22 Cum Volume of Sand required = 2/7 X 1.54 = 0.44 Cum or 15.53 cft Got any Questions?

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